7
Adsorption, Ion Exchange, and Chromatography
$c_i$ = concentration of species i in the mobile phase (mass volume-1) or (mole volume-1)
$k_i$ = empirical constant for species i for isotherms (units vary)
$K_i$ = adsorption equilibrium constant for species i
$n_i$= internal parameter for isotherms (units vary)
$p_i$= partial pressure of species i (pressure)
$q_i$= amount of species i adsorbed per unit mass of adsorbent at equilibrium (mass mass-1) or (mole mass-1)
$q_{m_i}$ = amount of species i adsorbed per unit mass of adsorbent at maximum loading, where maximum loading corresponds to complete surface coverage (mass mass-1) or (mole mass-1)
linear isotherm:
\begin{equation}
\tag{31.1}
q_i=k_ip_i
\end{equation}
Freundlich isotherm:
\begin{equation}
\tag{31.2}
q_i=k_ip_i^{1/n_i}
\end{equation}
Langmuir isotherm:
\begin{equation}
\tag{31.3}
q_i=\frac{K_iq_{m_i}p_i}{1+K_ip_i}
\end{equation}
chromatography equilibrium:
\begin{equation}
\tag{31.4}
K_i=\frac{q_i}{c_i}
\end{equation}
Watch a video from LearnChemE for an explanation about the concept of adsorption: Adsorption Introduction (8:49)
Modeling Differential Chromatography
$\alpha_i$ = average partitioning of species i between the bulk fluid and sorbent (unitless)
$\epsilon_b$ = sorbent porosity, ranges from 0 to 1 (unitless)
$\epsilon^*_{p,i}$ = inclusion porosity, accounts for accessibility of sorbent pores to species i (unitless)
$\tau_f$ = sorbent tortuosity factor, usually approximately 1.4 (unitless)
$\omega_i$ = fraction of solute in the mobile phase, relative to sorbed solute, at equilibrium (unitless)
$A$ = cross-sectional area of the column (area)
$c_{f,i}$ = concentration of species i in the mobile phase (mass volume-1) or (mol volume-1)
$D_{e,i}$ = effective diffusivity of species i within the sorbent pores (length2 time-1)
$E_i$ = coefficient that accounts for axial diffusion of species i and non-uniformities of flow (length2 time-1)
$H_i$ = height of theoretical chromatographic plate for species i (length)
$k_{a,i}$ = kinetic rate constant of adsorption of species i to the sorbent (time-1)
$k_{c,i}$ = mass transfer coefficient of species i in the mobile phase (length time-1)
$k_{c,i,tot}$ = overall mass transfer coefficient of species i (length time-1)
$K_{d,i}$ = equilibrium distribution coefficient of species i between the mobile phase and sorbent (unitless)
$L$ = length of column (length)
$m_{0_i}$ = amount of solute i fed to column (mass) or (mol)
$R_{1,2}$ = resolution of species 1 and 2 in the proposed operating condition (unitless)
$R_p$ = radius of sorbent particles (length)
$s_i$ = variance of the Gaussian peak of the distribution of species i along the column length (time)
$t$ = elapsed time since loading of the column (time)
${\overline t}_i$ = mean residence time of species i in the column (time)
$u$ = actual fluid velocity through the bed (length time-1)
$u_s$ = superficial fluid velocity through the bed (length time-1)
$z$ = position along the length of the column, in the direction of flow (length)
$z_{0,i}$ = mean position of species i along the length of the column as a function of time (length)
\begin{displaymath}
\tag{32.1}
z_{0,i}(t)=\omega_iut
\end{displaymath}
\begin{equation}
\tag{32.2}
\omega_i=\frac{1}{1+\frac{1-\epsilon_b}{\epsilon_b\alpha_i}}
\end{equation}
\begin{equation}
\tag{32.3}
\alpha_i=\frac{1}{\epsilon_{p,i}^*(1+K_{d,i})}
\end{equation}
\begin{equation}
\tag{32.4}
u=u_s/\epsilon_b
\end{equation}
\begin{equation}
\tag{32.5}
\overline t_i=\frac{L}{\omega_iu}
\end{equation}
\begin{equation}
\tag{32.6}
c_{f,i}(z,t)=\frac{m_{0_i}\omega_i}{A\epsilon_b(2\pi H_iz_0)^{0.5}}\textrm {exp}\left(\frac{-(z-z_0)^2}{2H_iz_0}\right)
\end{equation}
\begin{equation}
\tag{32.7}
H_i=2\left[\frac{E_i}{u}+\frac{\omega_i(1-\omega_i)R_pu}{3\alpha_ik_{ci,tot}}\right]
\end{equation}
\begin{displaymath}
\tag{32.8}
N_{{\rm Pe},i}=N_{\rm Re}N_{{\rm Sc},i}=\frac{2R_pu\epsilon_b}{D_i}
\end{displaymath}
if $N_{{\rm Pe},i}<<1$
\begin{displaymath}
\tag{32.9}
E_i=\frac{D_i}{\tau_f}
\end{displaymath}
else
\begin{displaymath}
\tag{32.10}
E_i=\frac{2R_pu\epsilon_b}{N_{{\rm Pe},E,i}}
\end{displaymath}
$N_{{\rm Pe},E,i}$ calculated by 15-61 or 15-62, Seader
\begin{equation}
\tag{32.11}
\frac{1}{k_{ci,tot}}=\frac{1}{k_{c,i}}+\frac{R_p}{5\epsilon_{p,i}^*D_{e,i}}+\frac{3}{R_pk_{a,i}\epsilon_{p,i}^*}\left[\frac{K_{d,i}}{1+K_{d,i}}\right]^2
\end{equation}
\begin{equation}
\tag{32.12}
s_i^2=\frac{\overline t_iH_i}{\omega_iu}
\end{equation}
\begin{equation}
\tag{32.13}
R_{1,2}=\frac{\textrm {abs}(\overline t_1-\overline t_2)}{2(s_1+s_2)}
\end{equation}
Example
1.0 g of species A is added to a chromatography column of cross-sectional area 1.0 m2 and length 1.0 m. Mobile phase is added at a flowrate of $4.0 \times 10^{-3}$ m3/s. Species A has a mass transfer coefficient of $2.0 \times 10^{-5}$ m/s in this solvent. The selected sorbent has a porosity of 0.40 m and average particle radius of $5.0\times 10^{-6}$ m. For species A in this sorbent, the inclusion porosity is 0.80, $K_d = 50$, $E = 2.0\times 10^{-8}$ m2/s, $k_a = 100$ s-1 and the effective diffusivity is $3.5\times 10^{-12}$ m2/s.
(a) When is mean expected elution time for species A?
(b) Plot the concentration profile for species A at 0.05 m increments along the column length in 10-minute increments, until all of the solute has eluted.
(c) Find the variance of the peak for species A in the proposed operating condition.
(d) The column feed also contains 1.0 g of species B. Species B has a mass transfer coefficient of $1.0\times 10^{-5}$ m/s in the mobile phase, inclusion porosity of 0.50, $K_d = 60$, $E = 3.0\times 10^{-8}$ m2/s, effective diffusivity of $4\times 10^{-12}$ m2/s and $k_a = 200$ s-1. What is the resolution of these two species in the proposed operating condition?