{"id":408,"date":"2025-03-31T03:20:47","date_gmt":"2025-03-31T03:20:47","guid":{"rendered":"https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/chapter\/example-5-6-design-capacity-from-in-situ-tests-spt\/"},"modified":"2026-03-16T14:05:26","modified_gmt":"2026-03-16T14:05:26","slug":"example-5-6-design-capacity-from-in-situ-tests-spt","status":"publish","type":"chapter","link":"https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/chapter\/example-5-6-design-capacity-from-in-situ-tests-spt\/","title":{"raw":"Example 5.6","rendered":"Example 5.6"},"content":{"raw":"Estimate the design capacity of the footing shown below according to AS 5100.3, using directly the SPT measurements in the loose-to-medium sandy foundation soil.\n\n[caption id=\"attachment_407\" align=\"aligncenter\" width=\"700\"]<img class=\"wp-image-407 size-full\" src=\"https:\/\/libraryresources.nse.org.ng\/wp-content\/uploads\/sites\/9\/2025\/02\/Example-5.6-e1743552420229.png\" alt=\"The figure on the left presents a footing of width 4 m resting on the soil surface. The groundwater table is found at -3m from the surface. The unit weight of soil is \u03b3 = 17 kN\/m^3. The total soil thickness considered is 1.B = 6 m. The figure on the right presents the variation of N-values with depth, up to a depth of 5.5 m. N-values range from N = 6 to N = 16.\" width=\"700\" height=\"510\"> Example 5.6. Problem description and input parameters.[\/caption]\n<h2>Answer:<\/h2>\nBefore applying Eq. 5.53 to estimate the bearing capacity, we must first find the corrected <em>N\u2032 <\/em>values for overburden stress, and the average corrected value <em>N\u2032<\/em>\u00a0over a depth 1.5<em>B <\/em>= 6 m. Application of Eqs. 5.51 and 5.52 for calculating the overburden stress correction factor <em>C<sub>N<\/sub><\/em> and accordingly the average <em>N<\/em><em>\u2032 <\/em>value for 6 m is presented in the table below.\n<table class=\"grid aligncenter\" style=\"border-collapse: collapse;width: 100%\" border=\"0\"><caption>Example 5.6. Calculation of average <em>N<\/em><em>\u2032\u00a0 <\/em>value.<\/caption>\n<tbody>\n<tr style=\"height: 15px\">\n<th style=\"width: 14.2857%;text-align: center;height: 15px\">Depth (m)<\/th>\n<th style=\"width: 14.2857%;text-align: center;height: 15px\"><em>N<\/em><\/th>\n<th style=\"width: 14.2857%;text-align: center;height: 15px\">Total stress (kPa)<\/th>\n<th style=\"width: 14.2857%;text-align: center;height: 15px\">Pore pressure (kPa)<\/th>\n<th style=\"width: 14.2857%;text-align: center;height: 15px\">Effective stress (kPa)<\/th>\n<th style=\"width: 14.2857%;text-align: center;height: 15px\"><em>C<sub>N<\/sub><\/em><\/th>\n<th style=\"width: 14.2857%;text-align: center;height: 15px\"><em>N\u2032 = NC<sub>N<\/sub><\/em><\/th>\n<\/tr>\n<tr style=\"height: 15px\">\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">1<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">8<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">17<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">0<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">17<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\"><s>2.373<\/s> 2.0*<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">16<\/td>\n<\/tr>\n<tr style=\"height: 15px\">\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">2.5<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">16<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">42.5<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">0<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">42.5<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">1.501<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">24<\/td>\n<\/tr>\n<tr style=\"height: 15px\">\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">4<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">12<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">68<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">10<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">58<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">1.285<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">15.4<\/td>\n<\/tr>\n<tr style=\"height: 15px\">\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">5.5<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">6<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">93.5<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">25<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">68.5<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">1.182<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">7.1<\/td>\n<\/tr>\n<tr style=\"height: 15px\">\n<td style=\"width: 85.7142%;height: 15px;text-align: right\" colspan=\"6\"><strong><em>N'<sub>average<\/sub><\/em><\/strong><\/td>\n<th style=\"width: 14.2857%;height: 15px;text-align: center\">15.62<\/th>\n<\/tr>\n<\/tbody>\n<\/table>\n<em>*Note: Use of C<sub>N<\/sub> values higher than 2.0 is not recommended<\/em>\n\nSubstituting in Eq. 5.53 while taking the groundwater table factors <em>C<sub>w1<\/sub><\/em>, <em>C<sub>w2<\/sub><\/em> from Table 5.7 yields:\n\n[latex]{q_f} = 9.57{N'_{average}}B\\left( {1.0 + 1.0 \\times \\dfrac{0}{4}} \\right) = 598{\\rm{ \\:kPa}}[\/latex]\n\nAs the bearing capacity is determined from SPT test results, the appropriate range of the geotechnical strength reduction factor <em>\u03c6<\/em><sub>g <\/sub>from Table 5.1 is <em>\u03c6<\/em><sub>g <\/sub>= 0.35 to 0.40. Selecting conservatively the lower bound of the proposed range, the design capacity is determined in terms of stress as:\n\n[latex]{\\varphi _g}{q_f} \\ge {S^ * } \\Rightarrow 0.35 \\times 598 \\ge {S^ * } \\Rightarrow {S^ * } \\le {\\rm{209 \\:kPa}}[\/latex]","rendered":"<p>Estimate the design capacity of the footing shown below according to AS 5100.3, using directly the SPT measurements in the loose-to-medium sandy foundation soil.<\/p>\n<figure id=\"attachment_407\" aria-describedby=\"caption-attachment-407\" style=\"width: 700px\" class=\"wp-caption aligncenter\"><img decoding=\"async\" class=\"wp-image-407 size-full\" src=\"https:\/\/libraryresources.nse.org.ng\/wp-content\/uploads\/sites\/9\/2025\/02\/Example-5.6-e1743552420229.png\" alt=\"The figure on the left presents a footing of width 4 m resting on the soil surface. The groundwater table is found at -3m from the surface. The unit weight of soil is \u03b3 = 17 kN\/m^3. The total soil thickness considered is 1.B = 6 m. The figure on the right presents the variation of N-values with depth, up to a depth of 5.5 m. N-values range from N = 6 to N = 16.\" width=\"700\" height=\"510\" srcset=\"https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/wp-content\/uploads\/sites\/9\/2025\/02\/Example-5.6-e1743552420229.png 700w, https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/wp-content\/uploads\/sites\/9\/2025\/02\/Example-5.6-e1743552420229-300x219.png 300w, https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/wp-content\/uploads\/sites\/9\/2025\/02\/Example-5.6-e1743552420229-65x47.png 65w, https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/wp-content\/uploads\/sites\/9\/2025\/02\/Example-5.6-e1743552420229-225x164.png 225w, https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/wp-content\/uploads\/sites\/9\/2025\/02\/Example-5.6-e1743552420229-350x255.png 350w\" sizes=\"(max-width: 700px) 100vw, 700px\" \/><figcaption id=\"caption-attachment-407\" class=\"wp-caption-text\">Example 5.6. Problem description and input parameters.<\/figcaption><\/figure>\n<h2>Answer:<\/h2>\n<p>Before applying Eq. 5.53 to estimate the bearing capacity, we must first find the corrected <em>N\u2032 <\/em>values for overburden stress, and the average corrected value <em>N\u2032<\/em>\u00a0over a depth 1.5<em>B <\/em>= 6 m. Application of Eqs. 5.51 and 5.52 for calculating the overburden stress correction factor <em>C<sub>N<\/sub><\/em> and accordingly the average <em>N<\/em><em>\u2032 <\/em>value for 6 m is presented in the table below.<\/p>\n<table class=\"grid aligncenter\" style=\"border-collapse: collapse;width: 100%\">\n<caption>Example 5.6. Calculation of average <em>N<\/em><em>\u2032\u00a0 <\/em>value.<\/caption>\n<tbody>\n<tr style=\"height: 15px\">\n<th style=\"width: 14.2857%;text-align: center;height: 15px\">Depth (m)<\/th>\n<th style=\"width: 14.2857%;text-align: center;height: 15px\"><em>N<\/em><\/th>\n<th style=\"width: 14.2857%;text-align: center;height: 15px\">Total stress (kPa)<\/th>\n<th style=\"width: 14.2857%;text-align: center;height: 15px\">Pore pressure (kPa)<\/th>\n<th style=\"width: 14.2857%;text-align: center;height: 15px\">Effective stress (kPa)<\/th>\n<th style=\"width: 14.2857%;text-align: center;height: 15px\"><em>C<sub>N<\/sub><\/em><\/th>\n<th style=\"width: 14.2857%;text-align: center;height: 15px\"><em>N\u2032 = NC<sub>N<\/sub><\/em><\/th>\n<\/tr>\n<tr style=\"height: 15px\">\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">1<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">8<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">17<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">0<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">17<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\"><span style=\"text-decoration: line-through;\">2.373<\/span> 2.0*<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">16<\/td>\n<\/tr>\n<tr style=\"height: 15px\">\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">2.5<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">16<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">42.5<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">0<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">42.5<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">1.501<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">24<\/td>\n<\/tr>\n<tr style=\"height: 15px\">\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">4<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">12<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">68<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">10<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">58<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">1.285<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">15.4<\/td>\n<\/tr>\n<tr style=\"height: 15px\">\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">5.5<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">6<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">93.5<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">25<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">68.5<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">1.182<\/td>\n<td style=\"width: 14.2857%;height: 15px;text-align: center\">7.1<\/td>\n<\/tr>\n<tr style=\"height: 15px\">\n<td style=\"width: 85.7142%;height: 15px;text-align: right\" colspan=\"6\"><strong><em>N&#8217;<sub>average<\/sub><\/em><\/strong><\/td>\n<th style=\"width: 14.2857%;height: 15px;text-align: center\">15.62<\/th>\n<\/tr>\n<\/tbody>\n<\/table>\n<p><em>*Note: Use of C<sub>N<\/sub> values higher than 2.0 is not recommended<\/em><\/p>\n<p>Substituting in Eq. 5.53 while taking the groundwater table factors <em>C<sub>w1<\/sub><\/em>, <em>C<sub>w2<\/sub><\/em> from Table 5.7 yields:<\/p>\n<p>[latex]{q_f} = 9.57{N'_{average}}B\\left( {1.0 + 1.0 \\times \\dfrac{0}{4}} \\right) = 598{\\rm{ \\:kPa}}[\/latex]<\/p>\n<p>As the bearing capacity is determined from SPT test results, the appropriate range of the geotechnical strength reduction factor <em>\u03c6<\/em><sub>g <\/sub>from Table 5.1 is <em>\u03c6<\/em><sub>g <\/sub>= 0.35 to 0.40. Selecting conservatively the lower bound of the proposed range, the design capacity is determined in terms of stress as:<\/p>\n<p>[latex]{\\varphi _g}{q_f} \\ge {S^ * } \\Rightarrow 0.35 \\times 598 \\ge {S^ * } \\Rightarrow {S^ * } \\le {\\rm{209 \\:kPa}}[\/latex]<\/p>\n","protected":false},"author":1,"menu_order":13,"template":"","meta":{"pb_show_title":"","pb_short_title":"Example 5.6","pb_subtitle":"Design capacity from in situ tests: SPT","pb_authors":[],"pb_section_license":""},"chapter-type":[],"contributor":[],"license":[],"class_list":["post-408","chapter","type-chapter","status-publish","hentry"],"part":325,"_links":{"self":[{"href":"https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/wp-json\/pressbooks\/v2\/chapters\/408","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/wp-json\/pressbooks\/v2\/chapters"}],"about":[{"href":"https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/wp-json\/wp\/v2\/types\/chapter"}],"author":[{"embeddable":true,"href":"https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/wp-json\/wp\/v2\/users\/1"}],"version-history":[{"count":1,"href":"https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/wp-json\/pressbooks\/v2\/chapters\/408\/revisions"}],"predecessor-version":[{"id":409,"href":"https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/wp-json\/pressbooks\/v2\/chapters\/408\/revisions\/409"}],"part":[{"href":"https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/wp-json\/pressbooks\/v2\/parts\/325"}],"metadata":[{"href":"https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/wp-json\/pressbooks\/v2\/chapters\/408\/metadata\/"}],"wp:attachment":[{"href":"https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/wp-json\/wp\/v2\/media?parent=408"}],"wp:term":[{"taxonomy":"chapter-type","embeddable":true,"href":"https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/wp-json\/pressbooks\/v2\/chapter-type?post=408"},{"taxonomy":"contributor","embeddable":true,"href":"https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/wp-json\/wp\/v2\/contributor?post=408"},{"taxonomy":"license","embeddable":true,"href":"https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/wp-json\/wp\/v2\/license?post=408"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}