{"id":104,"date":"2025-03-20T04:11:49","date_gmt":"2025-03-20T04:11:49","guid":{"rendered":"https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/chapter\/1-13-additional-problems\/"},"modified":"2026-03-16T13:53:56","modified_gmt":"2026-03-16T13:53:56","slug":"1-13-additional-problems","status":"publish","type":"chapter","link":"https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/chapter\/1-13-additional-problems\/","title":{"raw":"1.13 Additional problems","rendered":"1.13 Additional problems"},"content":{"raw":"<h2>1.13.1<\/h2>\nFor the design of a cut slope <em>(grey dashed line)<\/em>, 3 boreholes were drilled. The geological description of the encountered formations, their USCS classification and the SPT test results are provided below. Use the canvas to create a geotechnical model of the area to be introduced in the slope stability calculations, and propose the necessary parameters to be employed in the corresponding stability analyses.\n\n[caption id=\"attachment_103\" align=\"aligncenter\" width=\"800\"]<img class=\"wp-image-381 size-full\" src=\"https:\/\/libraryresources.nse.org.ng\/wp-content\/uploads\/sites\/9\/2024\/12\/Borehold-problem-e1743560789864.png\" alt=\"Cross-section of a slope with high point to the left, low point to the right. Three boreholes show from left to right - Borehole 1 with elevation 29.9m, Borehole 2 with elevation 23.0m, and Borehole 3 with elevation 17.2m. A grey dashed line shows the proposed straight cut into the slope.\" width=\"800\" height=\"495\"> Additional Problem 1.13.1. Problem description and input parameters.[\/caption]\n\n&nbsp;\n\n[caption id=\"attachment_103\" align=\"aligncenter\" width=\"1024\"]<img class=\"wp-image-383 size-large\" src=\"https:\/\/libraryresources.nse.org.ng\/wp-content\/uploads\/sites\/9\/2024\/12\/Borehole-problem-1024x523-1.png\" alt=\"Visual representations of the test results from each borehole (BH1 to BH3) on the sample slope, showing different soil layers with depth, as well as the variation of N-values with depth measured in each one of the boreholes\" width=\"1024\" height=\"523\"> Additional Problem 1.13.1. Problem description and input parameters.[\/caption]\n<h2>Answer:<\/h2>\n<em>Layer I: Dense clayey sand (SC) \u03c6\u2032\u2248<\/em><em>34<\/em><em>\u00b0<\/em><em>,<\/em> <em>\u03b3<\/em><em>=18 to 20 kN\/m<sup>3<\/sup><\/em>\n\n<em>Layer II: Very dense clayey gravels, poorely graded (GC-GP) \u03c6\u2032\u2248<\/em><em>40<\/em><em>\u00b0<\/em><em> to 43<\/em><em>\u00b0<\/em><em>, <\/em><em>\u03b3<\/em><em>=18 to 20 kN\/m<sup>3<\/sup><\/em>\n\n<em>Layer III: Fault zone: infinite strength for slope stability analyses<\/em>\n\n<em>Layer IV: Slightly to moderately weathered limestone (Lm): infinite strength for slope stability analyses<\/em>\n\n<hr>\n\n<h2>1.13.2<\/h2>\nFor the design of the deep foundation of a tall building, two (2) sampling boreholes were drilled and two (2) CPT soundings were performed. Results of the geotechnical investigation revealed a (more-or-less) consistent geotechnical profile: a medium-to-stiff low plasticity (PI \u2248 20%) clay formation prevails, interrupted by a loose-to-medium silty-clayey sand layer. The bedrock, a sandstone formation is encountered at depths 12.0 to 16.0 m.\n\nUse the <em>in situ <\/em>SPT and CPT test results, combined with the provided empirical relations\/charts, to determine the characteristic undrained shear strength <em>(S<sub>u<\/sub><\/em>) of the clay layer and the effective friction angle of the sand layer <em>(<\/em><em>\u03c6\u2032<\/em><em>). <\/em>Assume the bulk unit weight of the clay\/sand layers to be constant <em>\u03b3<\/em> = 17 kN\/m<sup>3<\/sup>.\n\n[caption id=\"attachment_103\" align=\"aligncenter\" width=\"1024\"]<img class=\"wp-image-102 size-large\" src=\"https:\/\/libraryresources.nse.org.ng\/wp-content\/uploads\/sites\/9\/2024\/12\/Part-1-Additional-problems-Figure-I-HR-1024x400.png\" alt=\"The graphs on the left of the figure presents the different geotechnical units identified during drilling of borehole BH1, and the variation of N60 values with depth measured from that borehole. The graphs on the right show the variation of cone resistance and friction ratio values measured in CPT1, and the soil behaviour type chart, where each pair of measurements is assigned of a different soil behaviour type zone.\" width=\"1024\" height=\"400\"> Additional Problem 1.13.2. Problem description and input parameters.[\/caption]\n\n[caption id=\"attachment_103\" align=\"aligncenter\" width=\"1024\"]<img class=\"wp-image-103 size-large\" src=\"https:\/\/libraryresources.nse.org.ng\/wp-content\/uploads\/sites\/9\/2026\/03\/Part-1-Additional-problems-Figure-II-HR-1024x418.png\" alt=\"The graphs on the left of the figure presents the different geotechnical units identified during drilling of borehole BH2, and the variation of N60 values with depth measured from that borehole. The graphs on the right show the variation of cone resistance and friction ratio values measured in CPT2, and the soil behaviour type chart, where each pair of measurements is assigned of a different soil behaviour type zone.\" width=\"1024\" height=\"418\"> Additional Problem 1.13.2. Problem description and input parameters.[\/caption]\n<table class=\"grid aligncenter\" style=\"border-collapse: collapse;width: 100%\" border=\"0\"><caption><strong>Example 1.13.2.<\/strong> CPT1 and CPT2 test results<\/caption>\n<tbody>\n<tr>\n<th style=\"width: 16.6667%;text-align: center\" colspan=\"3\">CPT1<\/th>\n<th style=\"width: 16.6667%;text-align: center\" colspan=\"3\">CPT2<\/th>\n<\/tr>\n<tr>\n<td style=\"width: 16.6667%;text-align: center\">Depth (m)<\/td>\n<td style=\"width: 16.6667%;text-align: center\"><em>q<sub>t<\/sub>\/p<sub>a<\/sub><\/em><\/td>\n<td style=\"width: 16.6667%;text-align: center\"><em>F<sub>R<\/sub><\/em> (%)<\/td>\n<td style=\"width: 16.6667%;text-align: center\">Depth (m)<\/td>\n<td style=\"width: 16.6667%;text-align: center\"><em>q<sub>t<\/sub>\/p<sub>a<\/sub><\/em><\/td>\n<td style=\"width: 16.6667%;text-align: center\"><em>F<sub>R<\/sub><\/em> (%)<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 16.6667%;text-align: center\">1<\/td>\n<td style=\"width: 16.6667%;text-align: center\">3.5<\/td>\n<td style=\"width: 16.6667%;text-align: center\">2.5<\/td>\n<td style=\"width: 16.6667%;text-align: center\">1<\/td>\n<td style=\"width: 16.6667%;text-align: center\">3<\/td>\n<td style=\"width: 16.6667%;text-align: center\">2.5<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 16.6667%;text-align: center\">2<\/td>\n<td style=\"width: 16.6667%;text-align: center\">4<\/td>\n<td style=\"width: 16.6667%;text-align: center\">1.3<\/td>\n<td style=\"width: 16.6667%;text-align: center\">2<\/td>\n<td style=\"width: 16.6667%;text-align: center\">5<\/td>\n<td style=\"width: 16.6667%;text-align: center\">0.8<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 16.6667%;text-align: center\">3<\/td>\n<td style=\"width: 16.6667%;text-align: center\">6<\/td>\n<td style=\"width: 16.6667%;text-align: center\">0.8<\/td>\n<td style=\"width: 16.6667%;text-align: center\">3<\/td>\n<td style=\"width: 16.6667%;text-align: center\">6.5<\/td>\n<td style=\"width: 16.6667%;text-align: center\">1<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 16.6667%;text-align: center\">4<\/td>\n<td style=\"width: 16.6667%;text-align: center\">5.5<\/td>\n<td style=\"width: 16.6667%;text-align: center\">1<\/td>\n<td style=\"width: 16.6667%;text-align: center\">4<\/td>\n<td style=\"width: 16.6667%;text-align: center\">9<\/td>\n<td style=\"width: 16.6667%;text-align: center\">1.5<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 16.6667%;text-align: center\">5<\/td>\n<td style=\"width: 16.6667%;text-align: center\">20<\/td>\n<td style=\"width: 16.6667%;text-align: center\">1<\/td>\n<td style=\"width: 16.6667%;text-align: center\">5<\/td>\n<td style=\"width: 16.6667%;text-align: center\">7<\/td>\n<td style=\"width: 16.6667%;text-align: center\">0.6<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 16.6667%;text-align: center\">6<\/td>\n<td style=\"width: 16.6667%;text-align: center\">11<\/td>\n<td style=\"width: 16.6667%;text-align: center\">0.6<\/td>\n<td style=\"width: 16.6667%;text-align: center\">6<\/td>\n<td style=\"width: 16.6667%;text-align: center\">4<\/td>\n<td style=\"width: 16.6667%;text-align: center\">4<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 16.6667%;text-align: center\">7<\/td>\n<td style=\"width: 16.6667%;text-align: center\">20<\/td>\n<td style=\"width: 16.6667%;text-align: center\">0.6<\/td>\n<td style=\"width: 16.6667%;text-align: center\">7<\/td>\n<td style=\"width: 16.6667%;text-align: center\">5.5<\/td>\n<td style=\"width: 16.6667%;text-align: center\">4.5<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 16.6667%;text-align: center\">8<\/td>\n<td style=\"width: 16.6667%;text-align: center\">17<\/td>\n<td style=\"width: 16.6667%;text-align: center\">0.5<\/td>\n<td style=\"width: 16.6667%;text-align: center\">8<\/td>\n<td style=\"width: 16.6667%;text-align: center\">6<\/td>\n<td style=\"width: 16.6667%;text-align: center\">2<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 16.6667%;text-align: center\">9<\/td>\n<td style=\"width: 16.6667%;text-align: center\">19<\/td>\n<td style=\"width: 16.6667%;text-align: center\">0.5<\/td>\n<td style=\"width: 16.6667%;text-align: center\">9<\/td>\n<td style=\"width: 16.6667%;text-align: center\">8<\/td>\n<td style=\"width: 16.6667%;text-align: center\">6<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 16.6667%;text-align: center\">10<\/td>\n<td style=\"width: 16.6667%;text-align: center\">5<\/td>\n<td style=\"width: 16.6667%;text-align: center\">3<\/td>\n<td style=\"width: 16.6667%;text-align: center\">10<\/td>\n<td style=\"width: 16.6667%;text-align: center\">9<\/td>\n<td style=\"width: 16.6667%;text-align: center\">3<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 16.6667%;text-align: center\">11<\/td>\n<td style=\"width: 16.6667%;text-align: center\">3<\/td>\n<td style=\"width: 16.6667%;text-align: center\">4.5<\/td>\n<td style=\"width: 16.6667%;text-align: center\">11<\/td>\n<td style=\"width: 16.6667%;text-align: center\">7.5<\/td>\n<td style=\"width: 16.6667%;text-align: center\">5<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 16.6667%;text-align: center\">12<\/td>\n<td style=\"width: 16.6667%;text-align: center\">11<\/td>\n<td style=\"width: 16.6667%;text-align: center\">2.5<\/td>\n<td style=\"width: 16.6667%;text-align: center\" colspan=\"3\" rowspan=\"4\"><\/td>\n<\/tr>\n<tr>\n<td style=\"width: 16.6667%;text-align: center\">13<\/td>\n<td style=\"width: 16.6667%;text-align: center\">10.5<\/td>\n<td style=\"width: 16.6667%;text-align: center\">6<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 16.6667%;text-align: center\">14<\/td>\n<td style=\"width: 16.6667%;text-align: center\">12<\/td>\n<td style=\"width: 16.6667%;text-align: center\">1.4<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 16.6667%;text-align: center\">15<\/td>\n<td style=\"width: 16.6667%;text-align: center\">13<\/td>\n<td style=\"width: 16.6667%;text-align: center\">2<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<h2>Answer:<\/h2>\n<em>Clay layer: S<sub>u<\/sub> = 20 kPa for depth z&lt;4m and S<sub>u<\/sub> = 20+2(z-6) kPa for depth z&gt;6m<\/em>\n\n<em>Sand layer: <\/em><em>\u03c6\u2032 =<\/em>\u00a0<em>30<\/em><em><sup>o<\/sup><\/em>","rendered":"<h2>1.13.1<\/h2>\n<p>For the design of a cut slope <em>(grey dashed line)<\/em>, 3 boreholes were drilled. The geological description of the encountered formations, their USCS classification and the SPT test results are provided below. Use the canvas to create a geotechnical model of the area to be introduced in the slope stability calculations, and propose the necessary parameters to be employed in the corresponding stability analyses.<\/p>\n<figure id=\"attachment_103\" aria-describedby=\"caption-attachment-103\" style=\"width: 800px\" class=\"wp-caption aligncenter\"><img decoding=\"async\" class=\"wp-image-381 size-full\" src=\"https:\/\/libraryresources.nse.org.ng\/wp-content\/uploads\/sites\/9\/2024\/12\/Borehold-problem-e1743560789864.png\" alt=\"Cross-section of a slope with high point to the left, low point to the right. Three boreholes show from left to right - Borehole 1 with elevation 29.9m, Borehole 2 with elevation 23.0m, and Borehole 3 with elevation 17.2m. A grey dashed line shows the proposed straight cut into the slope.\" width=\"800\" height=\"495\" \/><figcaption id=\"caption-attachment-103\" class=\"wp-caption-text\">Additional Problem 1.13.1. Problem description and input parameters.<\/figcaption><\/figure>\n<p>&nbsp;<\/p>\n<figure id=\"attachment_103\" aria-describedby=\"caption-attachment-103\" style=\"width: 1024px\" class=\"wp-caption aligncenter\"><img decoding=\"async\" class=\"wp-image-383 size-large\" src=\"https:\/\/libraryresources.nse.org.ng\/wp-content\/uploads\/sites\/9\/2024\/12\/Borehole-problem-1024x523-1.png\" alt=\"Visual representations of the test results from each borehole (BH1 to BH3) on the sample slope, showing different soil layers with depth, as well as the variation of N-values with depth measured in each one of the boreholes\" width=\"1024\" height=\"523\" \/><figcaption id=\"caption-attachment-103\" class=\"wp-caption-text\">Additional Problem 1.13.1. Problem description and input parameters.<\/figcaption><\/figure>\n<h2>Answer:<\/h2>\n<p><em>Layer I: Dense clayey sand (SC) \u03c6\u2032\u2248<\/em><em>34<\/em><em>\u00b0<\/em><em>,<\/em> <em>\u03b3<\/em><em>=18 to 20 kN\/m<sup>3<\/sup><\/em><\/p>\n<p><em>Layer II: Very dense clayey gravels, poorely graded (GC-GP) \u03c6\u2032\u2248<\/em><em>40<\/em><em>\u00b0<\/em><em> to 43<\/em><em>\u00b0<\/em><em>, <\/em><em>\u03b3<\/em><em>=18 to 20 kN\/m<sup>3<\/sup><\/em><\/p>\n<p><em>Layer III: Fault zone: infinite strength for slope stability analyses<\/em><\/p>\n<p><em>Layer IV: Slightly to moderately weathered limestone (Lm): infinite strength for slope stability analyses<\/em><\/p>\n<hr \/>\n<h2>1.13.2<\/h2>\n<p>For the design of the deep foundation of a tall building, two (2) sampling boreholes were drilled and two (2) CPT soundings were performed. Results of the geotechnical investigation revealed a (more-or-less) consistent geotechnical profile: a medium-to-stiff low plasticity (PI \u2248 20%) clay formation prevails, interrupted by a loose-to-medium silty-clayey sand layer. The bedrock, a sandstone formation is encountered at depths 12.0 to 16.0 m.<\/p>\n<p>Use the <em>in situ <\/em>SPT and CPT test results, combined with the provided empirical relations\/charts, to determine the characteristic undrained shear strength <em>(S<sub>u<\/sub><\/em>) of the clay layer and the effective friction angle of the sand layer <em>(<\/em><em>\u03c6\u2032<\/em><em>). <\/em>Assume the bulk unit weight of the clay\/sand layers to be constant <em>\u03b3<\/em> = 17 kN\/m<sup>3<\/sup>.<\/p>\n<figure id=\"attachment_103\" aria-describedby=\"caption-attachment-103\" style=\"width: 1024px\" class=\"wp-caption aligncenter\"><img decoding=\"async\" class=\"wp-image-102 size-large\" src=\"https:\/\/libraryresources.nse.org.ng\/wp-content\/uploads\/sites\/9\/2024\/12\/Part-1-Additional-problems-Figure-I-HR-1024x400.png\" alt=\"The graphs on the left of the figure presents the different geotechnical units identified during drilling of borehole BH1, and the variation of N60 values with depth measured from that borehole. The graphs on the right show the variation of cone resistance and friction ratio values measured in CPT1, and the soil behaviour type chart, where each pair of measurements is assigned of a different soil behaviour type zone.\" width=\"1024\" height=\"400\" srcset=\"https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/wp-content\/uploads\/sites\/9\/2024\/12\/Part-1-Additional-problems-Figure-I-HR-1024x400.png 1024w, https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/wp-content\/uploads\/sites\/9\/2024\/12\/Part-1-Additional-problems-Figure-I-HR-300x117.png 300w, https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/wp-content\/uploads\/sites\/9\/2024\/12\/Part-1-Additional-problems-Figure-I-HR-768x300.png 768w, https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/wp-content\/uploads\/sites\/9\/2024\/12\/Part-1-Additional-problems-Figure-I-HR-1536x600.png 1536w, https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/wp-content\/uploads\/sites\/9\/2024\/12\/Part-1-Additional-problems-Figure-I-HR-2048x800.png 2048w, https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/wp-content\/uploads\/sites\/9\/2024\/12\/Part-1-Additional-problems-Figure-I-HR-65x25.png 65w, https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/wp-content\/uploads\/sites\/9\/2024\/12\/Part-1-Additional-problems-Figure-I-HR-225x88.png 225w, https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/wp-content\/uploads\/sites\/9\/2024\/12\/Part-1-Additional-problems-Figure-I-HR-350x137.png 350w\" sizes=\"(max-width: 1024px) 100vw, 1024px\" \/><figcaption id=\"caption-attachment-103\" class=\"wp-caption-text\">Additional Problem 1.13.2. Problem description and input parameters.<\/figcaption><\/figure>\n<figure id=\"attachment_103\" aria-describedby=\"caption-attachment-103\" style=\"width: 1024px\" class=\"wp-caption aligncenter\"><img decoding=\"async\" class=\"wp-image-103 size-large\" src=\"https:\/\/libraryresources.nse.org.ng\/wp-content\/uploads\/sites\/9\/2026\/03\/Part-1-Additional-problems-Figure-II-HR-1024x418.png\" alt=\"The graphs on the left of the figure presents the different geotechnical units identified during drilling of borehole BH2, and the variation of N60 values with depth measured from that borehole. The graphs on the right show the variation of cone resistance and friction ratio values measured in CPT2, and the soil behaviour type chart, where each pair of measurements is assigned of a different soil behaviour type zone.\" width=\"1024\" height=\"418\" srcset=\"https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/wp-content\/uploads\/sites\/9\/2026\/03\/Part-1-Additional-problems-Figure-II-HR-1024x418.png 1024w, https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/wp-content\/uploads\/sites\/9\/2026\/03\/Part-1-Additional-problems-Figure-II-HR-300x122.png 300w, https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/wp-content\/uploads\/sites\/9\/2026\/03\/Part-1-Additional-problems-Figure-II-HR-768x313.png 768w, https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/wp-content\/uploads\/sites\/9\/2026\/03\/Part-1-Additional-problems-Figure-II-HR-1536x627.png 1536w, https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/wp-content\/uploads\/sites\/9\/2026\/03\/Part-1-Additional-problems-Figure-II-HR-2048x836.png 2048w, https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/wp-content\/uploads\/sites\/9\/2026\/03\/Part-1-Additional-problems-Figure-II-HR-65x27.png 65w, https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/wp-content\/uploads\/sites\/9\/2026\/03\/Part-1-Additional-problems-Figure-II-HR-225x92.png 225w, https:\/\/libraryresources.nse.org.ng\/fundamentalsoffoundationengineering\/wp-content\/uploads\/sites\/9\/2026\/03\/Part-1-Additional-problems-Figure-II-HR-350x143.png 350w\" sizes=\"(max-width: 1024px) 100vw, 1024px\" \/><figcaption id=\"caption-attachment-103\" class=\"wp-caption-text\">Additional Problem 1.13.2. Problem description and input parameters.<\/figcaption><\/figure>\n<table class=\"grid aligncenter\" style=\"border-collapse: collapse;width: 100%\">\n<caption><strong>Example 1.13.2.<\/strong> CPT1 and CPT2 test results<\/caption>\n<tbody>\n<tr>\n<th style=\"width: 16.6667%;text-align: center\" colspan=\"3\">CPT1<\/th>\n<th style=\"width: 16.6667%;text-align: center\" colspan=\"3\">CPT2<\/th>\n<\/tr>\n<tr>\n<td style=\"width: 16.6667%;text-align: center\">Depth (m)<\/td>\n<td style=\"width: 16.6667%;text-align: center\"><em>q<sub>t<\/sub>\/p<sub>a<\/sub><\/em><\/td>\n<td style=\"width: 16.6667%;text-align: center\"><em>F<sub>R<\/sub><\/em> (%)<\/td>\n<td style=\"width: 16.6667%;text-align: center\">Depth (m)<\/td>\n<td style=\"width: 16.6667%;text-align: center\"><em>q<sub>t<\/sub>\/p<sub>a<\/sub><\/em><\/td>\n<td style=\"width: 16.6667%;text-align: center\"><em>F<sub>R<\/sub><\/em> (%)<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 16.6667%;text-align: center\">1<\/td>\n<td style=\"width: 16.6667%;text-align: center\">3.5<\/td>\n<td style=\"width: 16.6667%;text-align: center\">2.5<\/td>\n<td style=\"width: 16.6667%;text-align: center\">1<\/td>\n<td style=\"width: 16.6667%;text-align: center\">3<\/td>\n<td style=\"width: 16.6667%;text-align: center\">2.5<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 16.6667%;text-align: center\">2<\/td>\n<td style=\"width: 16.6667%;text-align: center\">4<\/td>\n<td style=\"width: 16.6667%;text-align: center\">1.3<\/td>\n<td style=\"width: 16.6667%;text-align: center\">2<\/td>\n<td style=\"width: 16.6667%;text-align: center\">5<\/td>\n<td style=\"width: 16.6667%;text-align: center\">0.8<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 16.6667%;text-align: center\">3<\/td>\n<td style=\"width: 16.6667%;text-align: center\">6<\/td>\n<td style=\"width: 16.6667%;text-align: center\">0.8<\/td>\n<td style=\"width: 16.6667%;text-align: center\">3<\/td>\n<td style=\"width: 16.6667%;text-align: center\">6.5<\/td>\n<td style=\"width: 16.6667%;text-align: center\">1<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 16.6667%;text-align: center\">4<\/td>\n<td style=\"width: 16.6667%;text-align: center\">5.5<\/td>\n<td style=\"width: 16.6667%;text-align: center\">1<\/td>\n<td style=\"width: 16.6667%;text-align: center\">4<\/td>\n<td style=\"width: 16.6667%;text-align: center\">9<\/td>\n<td style=\"width: 16.6667%;text-align: center\">1.5<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 16.6667%;text-align: center\">5<\/td>\n<td style=\"width: 16.6667%;text-align: center\">20<\/td>\n<td style=\"width: 16.6667%;text-align: center\">1<\/td>\n<td style=\"width: 16.6667%;text-align: center\">5<\/td>\n<td style=\"width: 16.6667%;text-align: center\">7<\/td>\n<td style=\"width: 16.6667%;text-align: center\">0.6<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 16.6667%;text-align: center\">6<\/td>\n<td style=\"width: 16.6667%;text-align: center\">11<\/td>\n<td style=\"width: 16.6667%;text-align: center\">0.6<\/td>\n<td style=\"width: 16.6667%;text-align: center\">6<\/td>\n<td style=\"width: 16.6667%;text-align: center\">4<\/td>\n<td style=\"width: 16.6667%;text-align: center\">4<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 16.6667%;text-align: center\">7<\/td>\n<td style=\"width: 16.6667%;text-align: center\">20<\/td>\n<td style=\"width: 16.6667%;text-align: center\">0.6<\/td>\n<td style=\"width: 16.6667%;text-align: center\">7<\/td>\n<td style=\"width: 16.6667%;text-align: center\">5.5<\/td>\n<td style=\"width: 16.6667%;text-align: center\">4.5<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 16.6667%;text-align: center\">8<\/td>\n<td style=\"width: 16.6667%;text-align: center\">17<\/td>\n<td style=\"width: 16.6667%;text-align: center\">0.5<\/td>\n<td style=\"width: 16.6667%;text-align: center\">8<\/td>\n<td style=\"width: 16.6667%;text-align: center\">6<\/td>\n<td style=\"width: 16.6667%;text-align: center\">2<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 16.6667%;text-align: center\">9<\/td>\n<td style=\"width: 16.6667%;text-align: center\">19<\/td>\n<td style=\"width: 16.6667%;text-align: center\">0.5<\/td>\n<td style=\"width: 16.6667%;text-align: center\">9<\/td>\n<td style=\"width: 16.6667%;text-align: center\">8<\/td>\n<td style=\"width: 16.6667%;text-align: center\">6<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 16.6667%;text-align: center\">10<\/td>\n<td style=\"width: 16.6667%;text-align: center\">5<\/td>\n<td style=\"width: 16.6667%;text-align: center\">3<\/td>\n<td style=\"width: 16.6667%;text-align: center\">10<\/td>\n<td style=\"width: 16.6667%;text-align: center\">9<\/td>\n<td style=\"width: 16.6667%;text-align: center\">3<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 16.6667%;text-align: center\">11<\/td>\n<td style=\"width: 16.6667%;text-align: center\">3<\/td>\n<td style=\"width: 16.6667%;text-align: center\">4.5<\/td>\n<td style=\"width: 16.6667%;text-align: center\">11<\/td>\n<td style=\"width: 16.6667%;text-align: center\">7.5<\/td>\n<td style=\"width: 16.6667%;text-align: center\">5<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 16.6667%;text-align: center\">12<\/td>\n<td style=\"width: 16.6667%;text-align: center\">11<\/td>\n<td style=\"width: 16.6667%;text-align: center\">2.5<\/td>\n<td style=\"width: 16.6667%;text-align: center\" colspan=\"3\" rowspan=\"4\"><\/td>\n<\/tr>\n<tr>\n<td style=\"width: 16.6667%;text-align: center\">13<\/td>\n<td style=\"width: 16.6667%;text-align: center\">10.5<\/td>\n<td style=\"width: 16.6667%;text-align: center\">6<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 16.6667%;text-align: center\">14<\/td>\n<td style=\"width: 16.6667%;text-align: center\">12<\/td>\n<td style=\"width: 16.6667%;text-align: center\">1.4<\/td>\n<\/tr>\n<tr>\n<td style=\"width: 16.6667%;text-align: center\">15<\/td>\n<td style=\"width: 16.6667%;text-align: center\">13<\/td>\n<td style=\"width: 16.6667%;text-align: center\">2<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<h2>Answer:<\/h2>\n<p><em>Clay layer: S<sub>u<\/sub> = 20 kPa for depth z&lt;4m and S<sub>u<\/sub> = 20+2(z-6) kPa for depth z&gt;6m<\/em><\/p>\n<p><em>Sand layer: <\/em><em>\u03c6\u2032 =<\/em>\u00a0<em>30<\/em><em><sup>o<\/sup><\/em><\/p>\n","protected":false},"author":1,"menu_order":14,"template":"","meta":{"pb_show_title":"","pb_short_title":"1.13 Additional 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